假设数据是这样的，不难发现，其中父级roleCode有重复的，子级roleCode也有重复的，如何做到把重复的去掉，同时，又可以把不重复的合并到一起呢？
testTreeData: [
{
roleCode: 'staff',
roleNameCn: '员工',
children: [
{
roleCode: 'staff_01',
roleNameCn: '员工_01',
children: [
{
roleCode: 'staff_01_01',
roleNameCn: '员工_01_01'
}
]
}
]
},
{
roleCode: 'staff',
roleNameCn: '员工',
children: [
{
roleCode: 'staff_02',
roleNameCn: '员工_02',
children: [
{
roleCode: 'staff_02_01',
roleNameCn: '员工_02_01'
},
{
roleCode: 'staff_02_02',
roleNameCn: '员工_02_02'
}
]
}
]
},
{
roleCode: 'staff',
roleNameCn: '员工',
children: [
{
roleCode: 'staff_02',
roleNameCn: '员工_02',
children: [
{
roleCode: 'staff_webank_02_03',
roleNameCn: '员工_02_03'
},
{
roleCode: 'staff_webank_02_04',
roleNameCn: '员工_02_04'
}
]
}
]
},
{
roleCode: 'aaaaaaaa',
roleNameCn: '员工aaa'
},
{
roleCode: 'bbbbbbbb',
roleNameCn: '员工bbb'
}
]`
已解决
悬赏分：0
- 解决时间 2022-01-16 22:43
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回答2
最佳
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const result = [] testTreeData.forEach(child => merge(result, child)) function merge (source, child) { const curItem = source.find(item => item.roleCode === child.roleCode) if (!curItem) { source.push(child) } else { if (curItem.children && child.children) { child.children.forEach(childData => merge(curItem.children, childData)) } } }支持 0 反对 0 举报2022-01-16 16:00
